112 different area codes can be made.
Given, In a different plan for area codes, the first digit could be any number from 0 through 6 ,
So, total 7 digits are possible for 1st place (i.e. 0 1 2 3 4 5 6)
The second digit was either 7 or 8,
So, total 2 digits are possible for 2nd place (i.e. 7 8)
And the third digit could be any number except 0 or 6.
So, total possible digits are 8 for 3rd place (i.e. 1 2 3 4 5 7 8 9)
With this plan, we have to find how many different area codes are possible?
[tex]\text { total possible combinations }=7 \text { possibilities for } 1 \text { st place } \times 2 \text { for } 2 \text { nd place } \times 8 \text { for } 3 \text { rd place }[/tex]
[tex]\text { Total possible area codes }=7 \times 2 \times 8=14 \times 8=112[/tex]
Hence, 112 different area codes can be made.
