A park ranger at the top of a 700-meter station sees a fair that is 1800 meters from the base of the tower.

What is the angle of elevation in degrees?

Respuesta :

Answer:

The angle of elevation is 20.806°   .

Step-by-step explanation:

Given as :

The height of the station = 700 meter

The distance from the base of tower = 1800 meter

Let the angle of elevation = Ф

Now,

∵ Tan Ф = [tex]\dfrac{\text perpendicular}{\textrm Base}[/tex]

So,  Tan Ф = [tex]\dfrac{\text opposite measure}{\textrm Base measure}[/tex]

Or, Tan Ф = [tex]\dfrac{\textrm 700 m}{\textrm 1800 m}[/tex]

Or, Tan Ф = 0.38

∴   Ф = [tex]Tan^{-1}(0.38)[/tex]

I.e   Ф = 20.806°

Hence The angle of elevation is 20.806°   . Answer