A reaction of 0.028 g of magnesium with excess hydrochloric acid generated 31.0 mL of hydrogen gas. The gas was collected by water displacement in a 22 °C water bath. The barometric pressure in the lab that day was 746 mm Hg.Use Dalton's law to calculate the partial pressure of hydrogen gas in the gas-collecting tube.

Respuesta :

Answer :  The partial pressure of [tex]H_2[/tex] is, 726.2 mmHg

Solution :

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

[tex]P_T=p_{H_2}+p_{H_2O}[/tex]

where,

[tex]P_T[/tex] = total partial pressure = barometric pressure = 746 mmHg

[tex]P_{H_2}[/tex] = partial pressure of hydrogen gas = ?

[tex]P_{H_2O}[/tex] = partial pressure of water vapor = 19.8 mmHg  (assume)

Now put all the given values is expression, we get the partial pressure of the hydrogen gas.

[tex]746mmHg=p_{H_2}+19.8mmHg[/tex]

[tex]p_{H_2}=726.2mmHg[/tex]

Therefore, the partial pressure of [tex]H_2[/tex] is, 726.2 mmHg