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A piece of spacecraft debris initially at rest falls to the earth's surface from a height above the earth equal to one-half of the earth's radius. Find the speed at which the piece of debris hits the surface. Neglect air resistance and the gravitational pull of the moon.

Respuesta :

Answer:

[tex]v=25043.96\ m.s^{-1}[/tex]

Explanation:

As per given conditions we neglect the the air resistance and gravitational pull by the moon.

Height of fall of debris, [tex]h=32000\ km[/tex] (half of earth's radius)

Since the object is under free fall, it will go through the acceleration [tex]\rm g=9.8\ m.s^{-2}[/tex] and will finally impact the ground with a velocity given by:

[tex]v=\sqrt{2g.h}[/tex]

[tex]v=\sqrt{2\times 9.8\times 32000\times 10^3}[/tex]

[tex]v=25043.96\ m.s^{-1}[/tex]

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