Answer:
3z^2 + 3z - 6 =0
3
3 (z^2 + z -2) = 0
3(z+2)(z - 1) = 0
z + 2-2 = 0 - 2
z = -2
z - 1 + 1 = 0 + 1
z = 1
Step-by-step explanation:
- factor out the GCF (3) and divide everything by it, and then set it equal to zero.
- since you have a degree of 2, factor it into two binomials that start with the square root of the first term and end with the square root of the second term.
- 3=0 is extraneous solution so we leave it, then we set each binomial equal to zero to solve for z.
note: your solutions is based on the degree or the exponent of the polynomial or the function.
