Explanation:
From the first law of thermodynamics,
Δ[tex]Q[/tex]=Δ[tex]U[/tex]+[tex]W[/tex]
Where [tex]Q[/tex] is the heat given to the gas,
[tex]U[/tex] is the internal energy of the gas,
[tex]W[/tex] is the workdone by the gas.
When pressure is constant,
[tex]\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}[/tex]
[tex]V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}[/tex]
When pressure is constant,[tex]W=P[/tex]Δ[tex]V[/tex]
Where [tex]P[/tex] is pressure and [tex]V[/tex] is the volume of the gas.
Given [tex]P=1.5\times 10^{5}Pa[/tex]
Δ[tex]V=[/tex][tex]7.8-2.6=5.2m^{3}[/tex]
So,[tex]W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J[/tex]
Given that Δ[tex]U=6\times 10^{5}[/tex]
So,Δ[tex]Q=[/tex][tex]6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J[/tex]