Answer:
Pressure, [tex]P=1.33\times 10^6\ Pa[/tex]
Explanation:
Given that,
Radius of the opening, r = 0.45 mm = 0.00045 m
Weight of the pot, W = F = 0.848 N
To find,
The maximum pressure inside the pot
Solution,
We know that pressure inside the pot is equal to the force acting per unit area. It is given by :
[tex]P=\dfrac{F}{A}[/tex]
[tex]P=\dfrac{F}{\pi r^2}[/tex]
[tex]P=\dfrac{0.848\ N}{\pi (0.00045\ m)^2}[/tex]
[tex]P=1.33\times 10^6\ Pa[/tex]
So, the maximum pressure inside the pot is [tex]1.33\times 10^6\ Pa[/tex]. Hence, this is the required solution.
