Respuesta :
Answer:
Bird's speed immediately after swallowing = 4.52 m/s
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum
Mass of bird = 300 g = 0.3 kg
Velocity of bird = 5.5 m/s
Mass of insect = 10 g = 0.01 kg
Velocity of insect = -25 m/s ( opposite to the motion of bird)
Initial momentum = 0.3 x 5.5 + 0.01 x -25 = 1.4 kgm/s
Final mass = 0.3 + 0.01 = 0.31 kg
Initial momentum = Final momentum = 1.4 kgm/s
1.4 = 0.31 x Bird's speed immediately after swallowing
Bird's speed immediately after swallowing = 4.52 m/s
The speed of the bird immediately after swallowing, measured by an observer on the ground, is 4.52 m/s.
What is conservation of momentum?
Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.
When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
A 300 g bird flying along at 5.5 m/s sees a 10g insect heading straight toward it with a speed of 25 m/s (as measured by an observer on the ground, not by the bird).
Let suppose the bird's speed immediately after swallowing is v' m/s. Thus, by the conservation of momentum,
[tex](m_1v_1)+(m_2v_2)=(m_1+m_2)v'[/tex]
Put the values,
[tex](0.3\times5.5)+(0.01\times(-25))=(0.3+0.01)v'\\v'=4.52\rm\; m/s[/tex]
Thus, the speed of the bird immediately after swallowing, measured by an observer on the ground, is 4.52 m/s.
Learn more about the conservation of momentum here;
https://brainly.com/question/7538238
