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A charged capacitor stores energy U. Without connecting this capacitor to anything, dielectric having dielectric constant K is now inserted between the plates of the capacitor, completely filling the space between them. How much energy does the capacitor now store?

Respuesta :

Answer:

U / K

Explanation:

The energy stored in the capacitor is given by

[tex]U=\frac{q^{2}}{2C}[/tex]

where, q be the charge and C be the capacitance of the capacitor.

If a dielctric is inserted beteen the plates of capacitor having dielctric constant K, the new capacitance is C' = KC

The charge will remain same

The new energy stored is

[tex]U'=\frac{q^{2}}{2C'}[/tex]

[tex]U'=\frac{q^{2}}{2KC}[/tex]

U' = U / K

So, the energy reduces by the factor of K.

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