Respuesta :
Answer:
(a) 3224.27 N
(b) 3224.27 N
(c) 2.443 m/s^2
(d) 5.37 x 10^-22 m/s^2
Explanation:
Mass of satellite, m = 1320 kg
mas of earth, M = 6 x 10^24 kg
Radius of earth, r = 6.4 x 10^6 m
(a) The force of gravitation between the earth and the satellite is given by
[tex]F=G\frac{Mm}{d^{2}}[/tex]
where, d is the distance between the two objects
[tex]F=6.67\times10^{-11}\frac{6\times10^{24}\times 1320}{\left (2\times 6.4\times 10^{6} \right )^{2}}[/tex]
F = 3224.27 N
(b) The force on earth is same as the force on satellite.
F = 3224.27 N
(c) Acceleration of satellite = Force on satellite / mass of satellite
Acceleration of satellite = 3224.27 / 1320 = 2.443 m/s^2
(d) Acceleration of earth = Force on earth / mass of earth
Acceleration of satellite = 3224.27 / (6 x 10^24) = 5.37 x 10^-22 m/s^2
