A 2.0-kg block travels around a 0.40-m radius circle with an angular speed of 16 rad/s. The circle is parallel to the xy plane and is centered on the z axis, 0.60 m from the origin. What is the magnitude of the component in the xy plane of the angular momentum around the origin?

Respuesta :

To solve this problem it is necessary to apply the concept related to the Angular Moment.

By definition the angular momentum is given as

[tex]L=mvr[/tex]

Where

L= Angular momentum

m= mass

v= linear velocity

Recall that line speed can also be expressed as a function of angular velocity as

[tex]v = \omega R \rightarrow[/tex]where [tex]\omega[/tex] is the angular velocity and R the Radius

For the case described in the statement we have that there are two distances in different components, therefore the net radius would be given by

[tex]r^2 = R^2+d^2[/tex]

Where

R= Radius of the block

d= displacement in z-axis

Replacing with our values we have,

[tex]r^2=0.4^2+0.6^2[/tex]

[tex]r=0.7211m[/tex]

Replacing in the angular momentum equation, depending on the angular velocity we have to

[tex]L=m(\omega R)r[/tex]

[tex]L=(2)(16*0.4)(0.7211)[/tex]

[tex]L = 9.23008Kg.m/s[/tex]

Therefore the magnitude of the component in the xy plane of the angular momentum around the origin is [tex]9.23008Kg.m/s[/tex]