Respuesta :
Answer:
b C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻
e HC₂H₃O₂ + H₂O ⇄ H₃O⁺ + C₂H₃O₂⁻
f ka<<1
g. Weak acid molecules and water molecules
Explanation:
The water molecule could act as a base and as an acid, a molecule that have this property is called as amphoteric.
b The salt NaC₂H₃O₂ is dissolved in water as Na⁺ and C₂H₃O₂⁻. The reaction of the anion with water is:
C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻
Where the C₂H₃O₂⁻ is the base and water is the acid.
e. The reaction of HC₂H₃O₂ (acid) with water (base), produce:
HC₂H₃O₂ + H₂O ⇄ H₃O⁺ + C₂H₃O₂⁻
f. As the acetic acid (HC₂H₃O₂) is a week acid, the dissociation in C₂H₃O₂⁻ is not complete, that means that ka<<1
g. The ka for this reaction is 1,8x10⁻⁵, that means that there are more weak acid molecules (HC₂H₃O₂) than conjugate base ions. Also, the water molecules will be in higher proportion than hydronium ions.
I hope it helps!
HC2H3O2 is a weak acid so it dissociates to a small extent in solution.
When NaC2H3O2 is dissolved in water, the following reaction occurs;
[tex]NaC2H3O2(aq) ---->Na^+(aq) + C2H3O2-(aq)[/tex]
The ion combines with water as follows;
[tex]C2H3O2-(aq) + H2O(l) -----> HC2H3O2(aq) + OH-(aq)[/tex]
When HC2H3O2 is added to water, the following reaction occurs;
[tex]HC2H3O2(aq) + H2O(l) -----> H3O+(aq) + C2H3O2-(aq)[/tex]
We must note that HC2H3O2 is a weak acid. Weak acids only dissociate to a small extent in water therefore Ka << 1.
Since Ka << 1, it the follows that weak acid molecules and water molecules are present in the greatest concentration in solution because HC2H3O2 only dissociates to a very small extent.
Learn more: https://brainly.com/question/11969651