Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid = [tex]\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}[/tex]
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid = [tex]\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}[/tex]
Or, The surface area of right regular hexagonal pyramid = [tex]\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}[/tex]
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × [tex]\frac{171}{4}[/tex]
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer
