Answer:9 nickels and 19 dimes.
Step-by-step explanation:
Let [tex]n[/tex] be the number of nickels Kay has.
Let [tex]d[/tex] be the number of dimes Kay has.
Value of [tex]1[/tex] nickel is $[tex]0.05[/tex]
Value of [tex]n[/tex] nickels is $[tex]0.05n[/tex]
Value of [tex]1[/tex] dime is $[tex]0.1[/tex]
Value of [tex]d[/tex] nickels is $[tex]0.1dn[/tex]
Given that Kay has a total of [tex]28[/tex] coins.
So,[tex]n+d=28[/tex] ...(i)
Given that Kay has a total value of $[tex]2.35[/tex]
So,[tex]0.05n+0.1d=2.35[/tex] ...(ii)
Using (i) and (ii),
[tex]0.05n+0.1(28-n)=2.35\\0.05n+2.8-0.1n=2.35\\2.8-2.35=0.05n\\0.45=0.05n\\n=9[/tex]
[tex]d=28-n=28-9=19[/tex]
