Answer:
Approximately 4200 students will score less than 67 on the exam.
Step-by-step explanation:
Given:
Scores are normally distributed.
Mean score is, [tex]\mu=59[/tex]
Standard deviation is, [tex]\sigma=8[/tex]
Score is, [tex]x=67[/tex]
Total number of students, [tex]n=5000[/tex]
Now, the z score is given as:
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{67-59}{8}=\frac{8}{8}=1[/tex]
Since, the score is less than 67, therefore, z-score must be less than 1. So,
[tex]z<1[/tex]
From the z-score table, we observe that for z < 1, the population is 0.8413 or 84.13 % of the total population.
Therefore, the number of students scoring less than 67 is given as:
[tex]Number\ less\ than\ 67\ score=0.8413\times 5000=4206.7\approx 4200[/tex]
So, approximately 4200 students out of 5000 will get a score less than 67.
Answer:
Answer:
C
Step-by-step explanation:
Find P(X > 67)
using ( x - mean )/ standard deviation again you will get thi(1) which is equal to 0.8413....
0.8413 x 5000 is 4207
Step-by-step explanation:
