Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year. Write an equation for the situation? How long will it take for her to have around 5 sheep?

Respuesta :

The equation for the situation is [tex]y=200(\frac{2}{3})^{x}[/tex]

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is [tex]y=a(b)^{x}[/tex] , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is [tex]\frac{2}{3}[/tex]

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is [tex]y=a(b)^{x}[/tex] , where y represent the

   population in x years

∵ a = 200

∵ b = [tex]\frac{2}{3}[/tex]

∴ [tex]y=200(\frac{2}{3})^{x}[/tex]

The equation for the situation is [tex]y=200(\frac{2}{3})^{x}[/tex]

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ [tex]5=200(\frac{2}{3})^{x}[/tex]

- Divide both sides by 200

∴ [tex]0.025=(\frac{2}{3})^{x}[/tex]

- Insert ㏒ for both sides

∴ [tex]log(0.025)=log(\frac{2}{3})^{x}[/tex]

∴ [tex]log(0.025)=xlog(\frac{2}{3})[/tex]

- Divide both sides by [tex]log(\frac{2}{3})[/tex]

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly