Given that the measure of angle 6 is 1/8 of measure of angle 4. Find the measures of these two angles if a∥b.


Answer:
see explanation
Step-by-step explanation:
Let ∠4 be x then ∠6 is [tex]\frac{1}{8}[/tex] x
∠4 and ∠6 are same side interior angles and are supplementary, thus
x + [tex]\frac{1}{8}[/tex]x = 180
Multiply through by 8 to clear the fraction
8x + x = 1440, that is
9x = 1440 ( divide both sides by 9 )
x = 160
Hence ∠4 = 160° and ∠6 = 160° ÷ 8 = 20°
Answer:
[tex]m \angle 4 = 160 \°\\m \angle 6 = 20 \°[/tex]
Step-by-step explanation:
From the graph, we can say that
[tex]m \angle 6 + m \angle 4 = 180 \°[/tex]
Because they are consecutive interior angles, and they sum 180° by definition. So, the reason of third statement is "by definition of consecutive interior angles".
We already know that
[tex]m \angle 6 = \frac{1}{8} \times m \angle 4[/tex]
But,
[tex]m \angle 6 + m \angle 4 = 180 \°\\m \angle 6 = 180\° - m \angle 4[/tex]
Replacing this, we have
[tex]180\° - m \angle 4=\frac{1}{8}(m \angle 4)\\(\frac{1}{8}+1) (m\angle 4)=180\°\\\frac{9}{8}(m\angle 4) = 180 \°\\ m \angle 4 = \frac{180(8)}{9}= 160\°[/tex]
Then,
[tex]m \angle 6 + m \angle 4 = 180 \°\\m \angle 6 + 160\° =180\°\\m \angle 6 = 180-160=20[/tex]
Therefore, the measures of these two angles are
[tex]m \angle 4 = 160 \°\\m \angle 6 = 20 \°[/tex]