Respuesta :

Answer:

The statement is true

Step-by-step explanation:

we know that

In a Rhombus the diagonals bisect opposite angles.

therefore

diagonal AD bisect angle D and angle A

so

m∠CDA≅m∠BDA

m∠CAD≅m∠BAD

diagonal CB bisect angle C and angle B

so

m∠ACB≅m∠DCB

m∠ABC≅m∠DBC