Respuesta :
Company will need 105 gallons of premium antifreeze solution. And 135 gallons of water to be mixed to get a solution which contains 84 gallons of pure antifreeze in 240 gallon mixture that 240 gallons of a mixture that contains 35% pure antifreeze.
Solution:
Given that chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture.
The premium antifreeze solution contains 80% pure antifreeze.
The company wants to obtain 240 gallons of a mixture that contains 35% pure antifreeze.
Need to calculate gallons of water and gallons of the premium antifreeze solution must be mixed to get 240 gallons of 35% pure antifreeze.
Lets first calculate quantity of pure antifreeze required for 240 gallons having 35% of pure antifreeze.
35% of 240 gallons = 0.35 x 240 = 84 gallons of pure antifreeze.
Now need to determine quantity of premium antifreeze solution which will containing 84 gallons of pure antifreeze.
As premium antifreeze solution contains 80% pure antifreeze
=> 1 gallon of premium antifreeze solution contains 80% of 1 gallon of pure antifreeze
=> 1 gallon of premium antifreeze solution contains 0.8 gallons of pure antifreeze
=> number of gallons of premium antifreeze solution which contains 0.8 gallons of pure antifreeze = 1
So number of gallons of premium antifreeze solution which contains 1 gallons of pure antifreeze [tex]=\frac{1}{0.8}=\frac{10}{8}=1.25 \text { gallons }[/tex]
=> Number of gallons of premium antifreeze solution which contains 84 gallons of pure antifreeze
= 84 x number of gallons of premium antifreeze solution which contains 1 gallons of pure antifreeze
= 84 x 1.25 = 105 gallons of premium antifreeze solution.
So company will need 105 gallons of premium antifreeze solution.
And (240 – 105 ) = 135 gallons of water to be mixed to get a solution which contains 84 gallons of pure antifreeze in 240 gallon mixture that 240 gallons of a mixture that contains 35% pure antifreeze.
