The acceleration is [tex]0.095 m/s^2[/tex]
Explanation:
We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. Therefore we can write:
[tex]\sum F = ma[/tex]
where:
[tex]\sum F[/tex] is the resultant force acting on the object
m is its mass
a is its acceleration
In this problem, we have the following forces acting on the system:
[tex]F_1 = 2500 N[/tex] (forward)
[tex]F_2 = -2400 N[/tex] (backward)
So, Newton's second law can be rewritten as:
[tex]F_1 -F_2 = ma[/tex]
where:
m = 1050 kg is the mass of all the students
Solving the formula for a, we find the acceleration of the system:
[tex]a=\frac{F_1-F_2}{m}=\frac{2500+(-2400)}{1050}=0.095 m/s^2[/tex]
Learn more about Newton's second law:
brainly.com/question/3820012
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