Answer:
A quadratic equation that has roots x=0 and x=6/5 can be derived by
(x-0)(x-6/5) = 0
x(x-6.5)= 0
x^2 - 6.5x =0
To get it in its standard form, you need to complete the square of the quadratic function aka get it in the form of x^2+ 2ax+ a^2.
x^2 -6.5x + (-6.5/2)^2 - (-6.5/2)^2=0
(x- 6.5/2)^2 - (-6.5/2)^2=0
