Answer:
Volume percent of a solution that has 10.0 g of ethanol= 12.37%
Volume percent of a solution that has 90.0 g of water = 87.69%
Explanation:
Volume Percent:
The volume percent helps us to indicate the concentration of the solution when the volume of the solute and volume of the solution is given by
[tex]Volume Percent=\frac{\text{Volume of the Solute}}{\text{Volume of Solution}}\times100%[/tex]
With respect to density 1mL of ethanol
=> 0.7893g or 10g of methanol contains
=> [tex]\frac{1}{0.7893}\times10[/tex]
=> 12.67mL
And for water = [tex]\frac{1}{0.9987} \times 90.0[/tex]
=> 90.12mL
Now total volume = 90.12+ 12.67 = 102.79mL
%(v/v) for water = [tex]\frac{90.12}{102.79}\times 100[/tex]
= 87.69%
%(v/v) for ethanol = [tex]\frac{12.67}{102.79}\times 100[/tex]
= 12.37%
