Answer:
a)6,7,8,9 and 10th term is 15.
b)1,3,5,7 and 10th term is 19.
Step-by-step explanation:
Given a) n+5
b)2n-1
Solution for a) n+5
Taking the value of n is 1 we get the first term of the sequence;
[tex]n+5=1+5=6[/tex]
Similarly taking the value of n 2,3,4 we get;
[tex]2+5=7\\3+5=8\\4+5=9[/tex]
And for 10th term we take the value of n is 10 and get;
[tex]n+5=10+5=15[/tex]
So the solution for 1st sequence is 6,7,8,9 and 10th term is 15.
Solution for b)2n-1
Taking the value of n is 1 we get the first term of the sequence;
[tex]2n-1=2\times1-1=2-1=1[/tex]
Similarly taking the value of n 2,3,4 we get;
[tex]2n-1=2\times2-1=4-1=3\\2\times3-1=6-1=5\\2\times4-1=8-1=7[/tex]
And for 10th term we take the value of n is 10 and get;
[tex]2n-1=2\times10-1=20-1=19[/tex]
So the solution for 2nd sequence is 1,3,5,7 and 10th term is 19.
