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A 60 - kilogram person stands on a compression spring . The spring constant is 2500 Newtons per meter .
What is the displacement of the spring ?
A) 0.00392m
B)0.024m
C)0.1176 m
D) 0.2352m

Respuesta :

Answer:0.2352[tex]m[/tex]

Step-by-step explanation:

Let the mass of the person be [tex]m[/tex].

Let the spring constant be [tex]k[/tex].

Let the displacement in spring be [tex]x[/tex]

Let the acceleration due to gravity be [tex]g[/tex]

As it is given that the person just stands,the forces are balanced.

So,[tex]mg=kx[/tex]

Given,

[tex]m=60Kg\\k=2500Nm^{-1}\\g=9.8ms^{-2}[/tex]

[tex]60\times 9.8=2500\times x\\x=\frac{588}{2500}=0.2352m[/tex]

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