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A skidder dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the skidder is applying a force of 1850 N what is the coefficient of friction between the log and the ground

Respuesta :

Answer:

The coefficient of friction between the log and the ground is, μₓ = 0.3630

Explanation:

Given data,

The skidder dragging the mass, m = 520 kg

The acceleration of the mass, a = 3.5 m/s

The force applied by the skidder, Fₓ = 1850 N

The kinetic frictional force is given by,

                       Fₓ = μₓ η

                      μₓ = Fₓ / η

Where  μₓ - the coefficient of the kinetic friction  

            η is the normal force acting on the mass due to gravitational force.

                          η = mg

                              = 520 x 9.8

                               = 5096 N

Substituting the values in the above equation,

                           μₓ = 1850 N / 5096 N

                                = 0.3630

Hence, the coefficient of friction between the log and the ground is, μₓ = 0.3630