Respuesta :
Answer:
The pressure decreases to 0.4 kilopascals.
Explanation:
Given:
Initial volume of the gas is, [tex]V_1=100\ ml=\frac{100}{1000}\ L=0.1\ L[/tex]
Final volume of the gas is, [tex]V_2=75\ L[/tex]
Initial pressure of the gas is, [tex]P_1=300\ kPa[/tex]
Final pressure of the gas is, [tex]P_2=?[/tex]
The temperature is constant (isothermal) for the given process.
We know that for a process of constant temperature, pressure of a gas varies inversely with volume. This fact is known as Boyle's Law. So, as per Boyle's Law, the product of pressure and volume of a gas undergoing isothermal process is a constant. Therefore,
[tex]P_1V_1=P_2V_2\\300\times 0.1=P_2\times 75\\30=75P_2\\P_2=\frac{30}{75}=0.4\ kPa[/tex]
Therefore, the pressure of the gas gets reduced to a value of 0.4 kPa.
