Answer:
k = 0.2980
Step-by-step explanation:
Given:
number of months t =3
number of hits y = 10000
The equation is modeled as
[tex]y= 4090e^{kt}[/tex]
We need to find value of k.
Now Substituting the values in above equation we get.
[tex]10000= 4090e^3k\\e^{3k}=\frac{10000}{4090}\\\\[/tex]
Now taking Anti log on both side to remove e we get,
[tex]3k = \ ln \frac{10000}{4090}\\\\3k = 0.8940\\k = \frac{0.8940}{3}= 0.2980[/tex]
Hence the value of k = 0.2980.