We have that for the Question "What volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol)?" it can be said that The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is
V=0.862L
From the question we are told
What volume of 0.20MNaCl (aq) contains 10.0g of NaCl (molar mass 58g/mol)?
Generally the equation for the morality is mathematically given as
[tex]M=\frac{moles of NaCl}{Volume of sol}\\\\0.20=\frac{10/58}{V}\\\\[/tex]
V=0.862L
Therefore
The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is
V=0.862L
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The volume of 0.20M NaCl solution containing 10g of NaCl will be 34.48 ml.
Molarity can be defined as the moles of solute in a liter of solution.
The 10 g of NaCl will be:
[tex]\rm moles\;=\;\dfrac{weight}{molecular\;weight}[/tex]
moles of NaCl = [tex]\rm \dfrac{10\;g}{58\;g/mol}[/tex]
Moles of NaCl = 0.172 moles
[tex]\rm Molarity\;=\;\dfrac{moles}{Volume\;(liters)}[/tex]
[tex]\rm Volume\;(liters)\;=\;moles\;\times\;molarity[/tex]
Volume of NaCl solution = 0.172 [tex]\times[/tex] 0.20
Volume of NaCl solution = 0.0344 liters
1 liter = 1000 ml
0.0344 liters = 0.0344 [tex]\times[/tex] 1000 ml
Volume of 0.20M NaCl solution containing 10g of NaCl will be 34.48 ml.
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