Answer:
Maximum height attained by the ball will be h = 28.416 m
Explanation:
We have given initial speed of the ball u = 23.6 m /sec
At maximum height velocity will be zero so final velocity v = 0 m/sec
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
From law of motion we know that [tex]v^2=u^2-2gh[/tex]
[tex]0^2=23.6^2-2\times 9.8\times h[/tex]
h = 28.416 m
So maximum height attained by the ball will be h = 28.416 m
