Answer:
Force in the rocket will be 4166.64 N
Explanation:
We have given mass of the rocket m = 3 kg
Rocket acquires a speed of 50 m sec so final speed v = 50 m/sec
Initial speed u = 0 m/sec
Distance traveled s = 90 cm = 0.9 m
From third equation of motion we know that [tex]v^2=u^2+2as[/tex]
[tex]50^2=0^2+2\times a\times 0.9[/tex]
[tex]a=1388.88m/sec^2[/tex]
From newton's law we F = ma
So force will be [tex]F=1388.88\times 3=4166.64N[/tex]
So force in the rocket will be 4166.64 N