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You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1105 M NaOH. If you add 20.00 mL of HCOOH to the beaker before titrating, approximately what volume of NaOH will be required to reach the end point? A) 11.1 mL B) 72.4 mL C) 20.0 mL D) 36.2 mL

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D)  36.2 mL of 0.1105 M NaOH solution

Explanation:

We have the following chemical reaction:

HCOOH + NaOH → HCOONa + H₂O

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume

number of moles of HCOOH = 0.2 × 20 = 4 mmoles

From the chemical reaction we see that 1 mmole of HCOOH will react with 1 mmole of NaOH so 4 mmoles of HCOOH will react with 4 mmoles of NaOH.

volume =  number of moles / molar concentration

volume of NaOH solution = 4 / 0.1105 = 36.2 mL

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molar concentration

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