Answer with Step-by-step explanation:
Since we have given that
[tex]W(h)=49+2.2(h-60)[/tex]
if the height of male = 6 foot
1 foot = 12 inches
6 foot = 72 inches
So, the ideal weight would be
[tex]W(6)=49+2.2(72-60)\\\\W(6)=49+2.2\times 12\\\\W(6)=75.4\ kg[/tex]
Now, Express the height h as a function of weight W.
[tex]w=49+2.2(h-60)\\\\w-49=2.2(h-60)\\\\\dfrac{w-49}{2.2}=h-60\\\\\dfrac{w-49}{2.2}+60=h(W)[/tex]
Now, W(h(W) ) is given by
[tex]W(h(W))=49+2.2(\dfrac{w-49}{2.2}+60-60)\\\\W(h(W))=49+w-49\\\\W(h(W)=w[/tex]
Similarly,
[tex]h(W(h))=\dfrac{49+2.2(h-60)-49}{2.2}+60\\\\h(W(h))=\dfrac{2.2(h-60)}{2.2}+60\\\\h(W(h))=h-60+60\\\\h(W(h))=h[/tex]