Answer:
(a) Magnetic moment will be [tex]17.212\times 10^{-4}A-m^2[/tex]
(b) Torque will be [tex]6.024\times 10^{-4}N-m[/tex]
Explanation:
We have given dimension of the rectangular 5.4 cm × 8.5 cm
So area of the rectangular coil [tex]A=5.4\times 8.5=45.9cm^2=45.9\times 10^{-4}m^2[/tex]
Current is given as [tex]i=15mA=15\times 10^{-3}A[/tex]
Number of turns N = 25
(A) We know that magnetic moment is given by [tex]magnetic\ moment=NiA=25\times 45.9\times 10^{-4}\times 15\times 10^{-3}=17.212\times 10^{-4}A-m^2[/tex]
(b) Magnetic field is given as B = 0.350 T
We know that torque is given by [tex]\tau =BINA=0.350\times 15\times 10^{-3}\times 25\times 45.9\times 10^{-4}=6.024\times 10^{-4}N-m[/tex]
