Answer: [tex]5.81\times 10^6J/mol[/tex]
Explanation:
Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.
[tex]C_{12}H_{22}O_{11}(s)+12O_2\rightarrow 12CO_2(g)+11H_2O(g)[/tex]
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.05392g}{342g/mol}=1.577\times 10^{-4}moles[/tex]
Thus [tex]1.577\times 10^{-4}moles[/tex] of sucrose releases = 916.6 J of heat
1 mole of sucrose releases =[tex]\frac{916.6}{1.577\times 10^{-4}}\times 1=5.81\times 10^6J[/tex] of heat
Thus ∆H value for the combustion reaction is [tex]5.81\times 10^6J/mol[/tex]
