The values of x are: 0, -8 and 2/5
Step-by-step explanation:
Given equation is:
[tex]5x^3+38x^2-16x=0[/tex]
First of all, we can take x as common
[tex]x(5x^2+38x-16) = 0\\[/tex]
Then making factors of 38 we get
[tex]x(5x^2+40x-2x-16)=0\\x[5x(x+8)-2(x+8)]=0\\x[(5x-2)(x+8)] = 0\\x(5x-2)(x+8) = 0[/tex]
For values of x,
[tex]x = 0\\x+8 = 0 => x=-8\\5x-2 = 0 => 5x = 2 => x=\frac{2}{5}[/tex]
Hence,
The values of x are: 0, -8 and 2/5
Keywords: Factorization, Roots
Learn more about factorization at:
- brainly.com/question/2048256
- brainly.com/question/2115122
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