The new electric force is equal to the original force
Explanation:
The electrostatic force between two charges is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1, q2 are the two charges
r is the separation between the charges
In this problem, at the beginning we have
[tex]q_1 = -q\\q_2 = -q\\r=r[/tex]
So the force is
[tex]F=k\frac{(-q)(-q)}{r^2}=\frac{kq^2}{r^2}[/tex]
Later, the amount of both charges is doubled, so:
[tex]q_1' = -2q\\q_2' = -2q[/tex]
and the separation is doubled as well:
[tex]r'=2r[/tex]
So the new force is:
[tex]F'=k\frac{(-2q)(-2q)}{(2r)^2}=\frac{kq^2}{r^2}=F[/tex]
This means that the new electric force is equal to the original force.
Learn more about electric force:
brainly.com/question/8960054
brainly.com/question/4273177
#LearnwithBrainly
