Answer:
The hill should be not less than 0.625 m high
Explanation:
This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that
[tex]E_m=U+K[/tex] is constant, being U the potential energy and K the kinetic energy
[tex]U=mgh[/tex]
[tex]K=\frac{mv^2}{2}[/tex]
When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.
The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.
[tex]mgh=\frac{mv^2}{2}[/tex]
We can solve for h:
[tex]h=\frac{v^2}{2g}=\frac{3.5^2}{2(9.8)}=0.625m[/tex]
The hill should be not less than 0.625 m high
The hill should have a height of 0.625 m and above.
This is defined as the measurement of the vertical position of a body.
Total mechanical energy = Potential energy + kinetic energy.
Potential energy = mgh
Kinetic energy = 1/2mv²
We can infer that:
mgh = 1/2mv²
h = v² / 2g
= (3.5)² / 2(9.8)
= 0.625m.
Read more about Height here https://brainly.com/question/73194
