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A chemist must dilute 58.0 mL of 13.5 M aqueous silver nitrate (AgNO3)solution until the concentration falls to 5.00 M . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Round your answer to 3significant digits.

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To develop this problem it is necessary to apply the concepts related to Continuity.

The continuity equation could be defined as

[tex]m_1V_1=m_2V_2[/tex]

Where,

[tex]m_i[/tex]= Mass

[tex]V_i =[/tex] Volume

Our values are given as

[tex]m_1[/tex]= 13.5M

[tex]m_2[/tex]= 5M

[tex]V_1[/tex]= 58.0mL

Using the previous equation and rearrange to find [tex]V_2[/tex] we have,

[tex]m_1V_1=m_2V_2 \\V_2 = \frac{m_1V_1}{m_2}\\V_2 = \frac{(13.5)(58)}{(5)}\\V_2 = 156.6mL[/tex]

[tex]V_2 = 156.6mL(\frac{1L}{1000mL})=0.157L[/tex]

Therefore the final volume in liters would be 0.157L.

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