Respuesta :
Answer:
v = 0.509 m/s
Explanation:
Given that,
Mass of the ant, [tex]m = 12\ mg = 1.2\times 10^{-5}\ kg[/tex]
Force exerted, [tex]F = 47\ mN = 0.047\ N[/tex]
Time, [tex]t=0.13\ ms=0.00013\ s[/tex]
To find,
Speed with which it leave the ground.
Solution,
The change in momentum is equal to the product of force and time as :
[tex]F\times t=m(v-u)[/tex]
Since, u = 0
[tex]F\times t=mv[/tex]
[tex]v=\dfrac{Ft}{m}[/tex]
[tex]v=\dfrac{0.047\ N\times 0.00013\ s}{1.2\times 10^{-5}\ kg}[/tex]
v = 0.509 m/s
So, the speed with which it will leave the ground is 0.509 m/s.
The speed at which it leaves the ground is 0.5 m/s.
Calculating Impulse:
From Newton's Laws of motion, we know that force is the rate of change of momentum. That means when force is acted upon a body, the body experiences a change in momentum.
Now a sudden change in momentum due to a force applied for a short period of time is called impulse. Mathematically, the impulse is represented by:
Impulse = Δmv = Ft
where, m = 12 mg = 12×10⁻⁶ kg is the mass of the body
F = 47 mN = 47×10⁻³ N is the force
an t = 0.13 ms = 1.3×10⁻⁴ s
and v is the instantaneous velocity of the body
so,
[tex]v = \frac{Ft}{m} \\\\v=\frac{47\times10^{-3}\times1.3\times10^{-4}}{12\times10^{-6}}\\\\v=0.5\;m/s[/tex]
Learn more about impulse:
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