Answer:
The typical American spends 154.8 minutes (2.58 hours) per day watching television
We are supposed to find Do Internet users spend a different amount of time each day watching television?
[tex]H_0 : \mu = 154.8[/tex]
[tex]H_0 : \mu \neq 154.8[/tex]
n = 51
x = 128.7
[tex]\sigma =46.5[/tex]
We will use z test
[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
Substitute the values :
[tex]z=\frac{128.7-154.8}{\frac{46.5}{\sqrt{51}}}[/tex]
[tex]z=−4.0084[/tex]
α = 0.05
z at 95% = 1.96
z calculated < z critical
−4.0084< 1.96
So we fail to reject null hypothesis