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Find 3 consecutive even numbers where the product of the smaller two numbers is 64
less than the square of the largest number.

Respuesta :

Answer:

8

Step-by-step explanation:

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Answer:

8,10 and 12

Step-by-step explanation:

The numbers are

(x-2)* (x-4)  = x^ -64

Diistributive

x^-4x-2x+8 = x^-64

Subtract x^ on both sides (It will be cancelled)

-6x+8 = -64

Subtract 8 on both sides

-6x=-72

Divide both sides by -6

x=12

12-2=10

12-4=8

 8*10=80                     12*12=144            144-80=64

80+64=144

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