C₃₃H₂₄N₆O₆ is the molecular formula of the large molecule of tryptophan (which is a derivative of tryptophan molecule)
Explanation:
For the large tryptophan molecule we have been given the empirical formula C₁₁H₁₂N₂O₂. The molecular formula will be (C₁₁H₁₂N₂O₂)ₐ which have the molar mass of 612 g/mol.
Now we calculate the molar mass of (C₁₁H₁₂N₂O₂)ₐ:
molar mass of (C₁₁H₁₂N₂O₂)ₐ = (12 × 11 + 1 × 12 + 14 × 2 + 16 × 2) × a
molar mass of (C₁₁H₁₂N₂O₂)ₐ = 204a g/mol
Now to find "a" we do the following calculus:
204 × a = 612
a = 612 /204
a = 3
The molecular formula of large molecule of tryptophan will be:
(C₁₁H₁₂N₂O₂)₃ = C₃₃H₂₄N₆O₆
Learn more about:
empirical formula
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