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A box with a weight of 50 N rests on a horizontal surface. A person pulls horizontally on it with a force of 10 N and it does not move. To start it moving, a second person pulls vertically upward on the box. If the coefficient of static friction is 0.4, what is the smallest vertical force for which the box moves?

Respuesta :

Answer:

25 N

Explanation:

Given that

Weight ,mg = 50 N

m=Mass of the box

g=acceleration due to gravity

Horizontal force F= 10 N

Coefficient of friction  ,μ = 0.4

Lets take vertical force = R N

In vertical direction

R + N = mg

N= mg - R

The friction force Fr

Fr= μ N

Fr= μ ( mg - R)

To start the motion

F > Fr

10   > 0.4 ( 50 - R )

25  > 50 - R

R > 50 - 25  

R > 25 N

Therefore minimum force R= 25 N

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