Answer:
[tex]x= 28\°[/tex]
Step-by-step explanation:
We have labelled the given diagram and redrawn again in the attachment.
Also from the labelled diagram given below the given details are;
∠CPQ =[tex](5y-4)\°[/tex]
∠RQF =[tex]3y\°[/tex]
∠BRH =[tex](2x+13)\°[/tex]
∠CPQ = ∠PQF (Alternate Interior Angle)
∠PQF + ∠RQF =180° (Straight angle property)
Now Substituting the values we get;
[tex]5y-4+3y=180\\8y=180+4\\8y=184\\y=\frac{184}{8}=23\°[/tex]
∠RQF =[tex]3y\° = 3\times23 = 69\°[/tex]
∠RQF = ∠BRH (corresponding angles)
[tex]69=2x+13\\2x = 69 -13\\2x=56\\x = \frac{56}{2} = 23\°[/tex]
Hence x = 23°
