Answer:
[tex]e = 8.39\pi cos (120 \pi t)[/tex]
Explanation:
given,
Inductance of the inductor = 15.2 mH
i = Imax sin ωt
Imax = 4.60 A
f = ω/2π = 60.0 Hz
ω = 120 π
i = 4.6 sin (120π) t
[tex]e = -L \dfrac{di}{dt}[/tex]
[tex]e = - 15.2 \times 10^{-3} \dfrac{d}{dt}(4.6 sin (120 \pi t))[/tex]
[tex]e = - 15.2 \times 10^{-3}\times 4.6 (-120\pi cos (120 \pi t))[/tex]
[tex]e = 8.39\pi cos (120 \pi t)[/tex]
the self induced emf as a function of time t is equal to [tex]e = 8.39\pi cos (120 \pi t)[/tex]
