The slope, m, of a linear equation can be found using the formula m = StartFraction y 2 minus y a Over x 2 minus x 1 EndFraction., where the x- and y-values come from two ordered pairs, and (x1, y1) and (x2, y2).

What is an equivalent equation solved for y2?

y2 = mx2 – x1 + y1
y2 = mx2 – x1 – y1
y2 = m(x2 – x1) + y1
y2 = m(x2 – x1) – y1

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Answer: Third option.

Step-by-step explanation:

By definition, the slope of a line can be calculated with the following formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Since you need to solve for [tex]y_2[/tex] to find an equivalent expression, you can apply these steps:

1. You must multiply both sides of the equation by [tex](x_2-x_1)[/tex]:

[tex]m(x_2-x_1})=(\frac{y_2-y_1}{x_2-x_1})(x_2-x_1})\\\\m(x_2-x_1})=y_2-y_1[/tex]

2. Finally, you must add [tex]y_1[/tex] to both sides of the equation:

[tex]m(x_2-x_1})+y_1=y_2-y_1+y_1\\\\y_2=m(x_2-x_1})+y_1[/tex]

Answer:

C.y2 = m(x2 – x1) + y1

Step-by-step explanation: Just took the test and edg and got 100%, make sure to rate 5. and make me. branliest pls?