Answer:
3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.
Explanation:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
Moles of methane gas = [tex]\frac{1.28 g}{16 g/mol}=0.08 mol[/tex]
Moles of oxygen gas = [tex]\frac{10.1 g}{32 g/mol}=0.3156 mol[/tex]
According to reaction 1 moles of methane gas reacts with 2 mole of oxygen gas.
Then 0.08 moles of methane will recast with:
[tex]\frac{2}{1}\times 0.08 mol=0.16 mol[/tex] oxygen gas
As we can see that moles of methane are in limiting amount , so the amount moles of carbon dioxide will depend upon on moles of methane gas.
Limiting reagent = methane
According to reaction , 1 mole of methane gas gives 1 mol of carbon dioxide gas.
Then 0.08 moles of metahjen gas wuill give :
[tex]\frac{1}{1}\times 0.08 mol=0.08 mol[/tex] of carbon dioxide gas.
Mass of 0.08 mople sof carbon dioxde gas :
[tex]0.08 mol\times 44 g/mol=3.52 g[/tex]
3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.
