Respuesta :
Answer:
The correct option is: A. 0.168 M
Explanation:
Chemical reaction involved:
5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O
Given: For MnO₄⁻ solution-
Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;
For Fe²⁺ solution:
Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M
To find out the concentration of Fe²⁺ solution (M₂), we use the equation:
[tex]\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}[/tex]
[tex]\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}[/tex]
[tex]0.505 = M_{2}\times 3[/tex]
[tex]M_{2} = \frac{0.505}{3} = 0.168M[/tex]
Therefore, the concentration or molarity of Fe²⁺ solution: M₂ = 0.168 M
