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Part complete Horizontally-polarized light passes through a polarizing sheet, and only 25 % of the intensity of the incident light is transmitted through the sheet. What angle does the polarization of the light make with the horizontal after passing through the polarizer?

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Answer:

60°

Explanation:

I₀ = Intensity of unpolarized light

θ = Angle between the axis of the filter and polarization direction

Intensity of polarzied light

[tex]I=I_0cos\theta[/tex]

Here, the light that is transmitted is reduced by 25% that means

[tex]I=0.25I_0[/tex]

So,

[tex]0.25I_0=I_0cos^2\theta\\\Rightarrow cos^2\theta =0.25\\\Rightarrow cos\theta =5\\\Rightarrow \theta= cos^{-1}0.5\\\Rightarrow \theta=60^{\circ}[/tex]

∴ The angle between the axes of the polarizer and the analyzer is 60°