There is a contest being held at Company A. Company A employs forty people. The first 3 employees to correctly complete a riddle each receives an extra vacation day that year. What is the probability that those first 3 employees are in the order of Jack, Bill, and John?

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Answer:

The probability that those first 3 employees are in the order of Jack, Bill, and John is [tex]\frac{1}{59280}[/tex]

Step-by-step explanation:

Consider the provided information.

Company A employs forty people. We need to find the probability that those first 3 employees are in the order of Jack, Bill, and John?

First find the total number of ways;

We have 40 employees out of which we need to select only 3.

This can be written as: [tex]40\times 39 \times 38=59280[/tex]

The number of ways of selecting jack, bill and john in the same order = 1

[tex]Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}[/tex]

[tex]Probability=\frac{1}{59280}[/tex]

Therefore, the probability that those first 3 employees are in the order of Jack, Bill, and John is [tex]\frac{1}{59280}[/tex].